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11513045341321 is a prime number
BaseRepresentation
bin1010011110001001011011…
…1110100101010010001001
31111202122011220222101121121
42213202112332211102021
53002112204101410241
640253004153435241
72265534665503036
oct247422676452211
944678156871547
1011513045341321
113739722a50427
12135b37b70bb21
136568a215a5b4
142bb33d16838d
1514e7326e8ad1
hexa7896fa5489

11513045341321 has 2 divisors, whose sum is σ = 11513045341322. Its totient is φ = 11513045341320.

The previous prime is 11513045341309. The next prime is 11513045341327. The reversal of 11513045341321 is 12314354031511.

11513045341321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9265564635721 + 2247480705600 = 3043939^2 + 1499160^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11513045341321 is a prime.

It is not a weakly prime, because it can be changed into another prime (11513045341327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756522670660 + 5756522670661.

It is an arithmetic number, because the mean of its divisors is an integer number (5756522670661).

Almost surely, 211513045341321 is an apocalyptic number.

It is an amenable number.

11513045341321 is a deficient number, since it is larger than the sum of its proper divisors (1).

11513045341321 is an equidigital number, since it uses as much as digits as its factorization.

11513045341321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 11513045341321 its reverse (12314354031511), we get a palindrome (23827399372832).

The spelling of 11513045341321 in words is "eleven trillion, five hundred thirteen billion, forty-five million, three hundred forty-one thousand, three hundred twenty-one".