Base | Representation |
---|---|
bin | 1010011110001001011110… |
… | …0001001011101001000010 |
3 | 1111202122012120001012022212 |
4 | 2213202113201023221002 |
5 | 3002112213412130310 |
6 | 40253005120102122 |
7 | 2265535135550153 |
oct | 247422741135102 |
9 | 44678176035285 |
10 | 11513054411330 |
11 | 37397280858aa |
12 | 135b382764942 |
13 | 6568a3cb4a74 |
14 | 2bb34044992a |
15 | 14e7333db205 |
hex | a789784ba42 |
11513054411330 has 8 divisors (see below), whose sum is σ = 20723497940412. Its totient is φ = 4605221764528.
The previous prime is 11513054411291. The next prime is 11513054411357. The reversal of 11513054411330 is 3311445031511.
It can be written as a sum of positive squares in 2 ways, for example, as 11367801194689 + 145253216641 = 3371617^2 + 381121^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-4 number, since 4×115130544113304 (a number of 53 digits) contains 4444 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575652720557 + ... + 575652720576.
Almost surely, 211513054411330 is an apocalyptic number.
11513054411330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11513054411330 is a deficient number, since it is larger than the sum of its proper divisors (9210443529082).
11513054411330 is a wasteful number, since it uses less digits than its factorization.
11513054411330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1151305441140.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 11513054411330 its reverse (3311445031511), we get a palindrome (14824499442841).
The spelling of 11513054411330 in words is "eleven trillion, five hundred thirteen billion, fifty-four million, four hundred eleven thousand, three hundred thirty".
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