Base | Representation |
---|---|
bin | 11010001011011000010111… |
… | …011111110100100001100010 |
3 | 120002122102222101100200101200 |
4 | 122023120113133310201202 |
5 | 110042302334103213041 |
6 | 1044510330000142030 |
7 | 33151650430212363 |
oct | 3213302737644142 |
9 | 502572871320350 |
10 | 115131287554146 |
11 | 337589a53a3316 |
12 | 10ab526b307916 |
13 | 4c31aabc082b6 |
14 | 2060553b93b6a |
15 | d49c67d2a1b6 |
hex | 68b6177f4862 |
115131287554146 has 48 divisors (see below), whose sum is σ = 249498375287616. Its totient is φ = 38369827068768.
The previous prime is 115131287554117. The next prime is 115131287554399. The reversal of 115131287554146 is 641455782131511.
115131287554146 is a `hidden beast` number, since 1 + 1 + 5 + 1 + 3 + 1 + 2 + 87 + 554 + 1 + 4 + 6 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 115131287554092 and 115131287554101.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2886705921 + ... + 2886745803.
It is an arithmetic number, because the mean of its divisors is an integer number (5197882818492).
Almost surely, 2115131287554146 is an apocalyptic number.
115131287554146 is an abundant number, since it is smaller than the sum of its proper divisors (134367087733470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115131287554146 is a wasteful number, since it uses less digits than its factorization.
115131287554146 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66247 (or 66244 counting only the distinct ones).
The product of its digits is 4032000, while the sum is 54.
The spelling of 115131287554146 in words is "one hundred fifteen trillion, one hundred thirty-one billion, two hundred eighty-seven million, five hundred fifty-four thousand, one hundred forty-six".
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