Base | Representation |
---|---|
bin | 11010001011011000010111… |
… | …011111110100100101011111 |
3 | 120002122102222101100200202001 |
4 | 122023120113133310211133 |
5 | 110042302334103220044 |
6 | 1044510330000143131 |
7 | 33151650430213204 |
oct | 3213302737644537 |
9 | 502572871320661 |
10 | 115131287554399 |
11 | 337589a53a3526 |
12 | 10ab526b307aa7 |
13 | 4c31aabc0844c |
14 | 2060553b93cab |
15 | d49c67d2a2d4 |
hex | 68b6177f495f |
115131287554399 has 2 divisors, whose sum is σ = 115131287554400. Its totient is φ = 115131287554398.
The previous prime is 115131287554117. The next prime is 115131287554433. The reversal of 115131287554399 is 993455782131511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115131287554399 - 213 = 115131287546207 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115131287554399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115131287504399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565643777199 + 57565643777200.
It is an arithmetic number, because the mean of its divisors is an integer number (57565643777200).
Almost surely, 2115131287554399 is an apocalyptic number.
115131287554399 is a deficient number, since it is larger than the sum of its proper divisors (1).
115131287554399 is an equidigital number, since it uses as much as digits as its factorization.
115131287554399 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40824000, while the sum is 64.
The spelling of 115131287554399 in words is "one hundred fifteen trillion, one hundred thirty-one billion, two hundred eighty-seven million, five hundred fifty-four thousand, three hundred ninety-nine".
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