Base | Representation |
---|---|
bin | 11010001011011000010111… |
… | …011111110100100001000101 |
3 | 120002122102222101100200100121 |
4 | 122023120113133310201011 |
5 | 110042302334103212432 |
6 | 1044510330000141541 |
7 | 33151650430212322 |
oct | 3213302737644105 |
9 | 502572871320317 |
10 | 115131287554117 |
11 | 337589a53a329a |
12 | 10ab526b3078b1 |
13 | 4c31aabc08293 |
14 | 2060553b93b49 |
15 | d49c67d2a197 |
hex | 68b6177f4845 |
115131287554117 has 2 divisors, whose sum is σ = 115131287554118. Its totient is φ = 115131287554116.
The previous prime is 115131287554057. The next prime is 115131287554399. The reversal of 115131287554117 is 711455782131511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65801931961921 + 49329355592196 = 8111839^2 + 7023486^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115131287554117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115131237554117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565643777058 + 57565643777059.
It is an arithmetic number, because the mean of its divisors is an integer number (57565643777059).
Almost surely, 2115131287554117 is an apocalyptic number.
It is an amenable number.
115131287554117 is a deficient number, since it is larger than the sum of its proper divisors (1).
115131287554117 is an equidigital number, since it uses as much as digits as its factorization.
115131287554117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1176000, while the sum is 52.
The spelling of 115131287554117 in words is "one hundred fifteen trillion, one hundred thirty-one billion, two hundred eighty-seven million, five hundred fifty-four thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •