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115131520000000 = 21357731829
BaseRepresentation
bin11010001011011000100101…
…010110100010000000000000
3120002122110120120202011011101
4122023120211112202000000
5110042303323110000000
61044510405022224144
733151656252033160
oct3213304526420000
9502573516664141
10115131520000000
1133759004627329
1210ab5315125054
134c31b1811291a
1420605769c05a0
15d49c7d442e6a
hex68b6255a2000

115131520000000 has 896 divisors, whose sum is σ = 339946379735040. Its totient is φ = 38154240000000.

The previous prime is 115131519999917. The next prime is 115131520000037. The reversal of 115131520000000 is 25131511.

It is a tau number, because it is divible by the number of its divisors (896).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 138879999586 + ... + 138880000414.

Almost surely, 2115131520000000 is an apocalyptic number.

115131520000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115131520000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169973189867520).

115131520000000 is an abundant number, since it is smaller than the sum of its proper divisors (224814859735040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115131520000000 is an frugal number, since it uses more digits than its factorization.

115131520000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 928 (or 874 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 19.

Adding to 115131520000000 its reverse (25131511), we get a palindrome (115131545131511).

The spelling of 115131520000000 in words is "one hundred fifteen trillion, one hundred thirty-one billion, five hundred twenty million", and thus it is an aban number.