Search a number
-
+
1151322019 is a prime number
BaseRepresentation
bin100010010011111…
…1100011110100011
32222020102012220021
41010213330132203
54324214301034
6310124454311
740350034651
oct10447743643
92866365807
101151322019
11540989301
122816aa397
131546aca43
14acc9bdd1
156b1226b4
hex449fc7a3

1151322019 has 2 divisors, whose sum is σ = 1151322020. Its totient is φ = 1151322018.

The previous prime is 1151322001. The next prime is 1151322023. The reversal of 1151322019 is 9102231511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1151322019 - 25 = 1151321987 is a prime.

It is a super-2 number, since 2×11513220192 = 2651084782868472722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1151321984 and 1151322002.

It is not a weakly prime, because it can be changed into another prime (1151322079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575661009 + 575661010.

It is an arithmetic number, because the mean of its divisors is an integer number (575661010).

Almost surely, 21151322019 is an apocalyptic number.

1151322019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151322019 is an equidigital number, since it uses as much as digits as its factorization.

1151322019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 25.

The square root of 1151322019 is about 33931.1364236449. The cubic root of 1151322019 is about 1048.0908676892.

The spelling of 1151322019 in words is "one billion, one hundred fifty-one million, three hundred twenty-two thousand, nineteen".