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115132420485367 is a prime number
BaseRepresentation
bin11010001011011001011011…
…000001100111000011110111
3120002122112220100011112212021
4122023121123001213003313
5110042312144121012432
61044511034230534011
733152020465033015
oct3213313301470367
9502575810145767
10115132420485367
113375942696030a
1210ab5526807307
134c31c2c8491bc
1420606204258b5
15d49cd2518697
hex68b65b0670f7

115132420485367 has 2 divisors, whose sum is σ = 115132420485368. Its totient is φ = 115132420485366.

The previous prime is 115132420485301. The next prime is 115132420485391. The reversal of 115132420485367 is 763584024231511.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115132420485367 is a prime.

It is a super-2 number, since 2×1151324204853672 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115132420485767) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566210242683 + 57566210242684.

It is an arithmetic number, because the mean of its divisors is an integer number (57566210242684).

Almost surely, 2115132420485367 is an apocalyptic number.

115132420485367 is a deficient number, since it is larger than the sum of its proper divisors (1).

115132420485367 is an equidigital number, since it uses as much as digits as its factorization.

115132420485367 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 52.

The spelling of 115132420485367 in words is "one hundred fifteen trillion, one hundred thirty-two billion, four hundred twenty million, four hundred eighty-five thousand, three hundred sixty-seven".