Base | Representation |
---|---|
bin | 11010001011011001011011… |
… | …000001100111000100001110 |
3 | 120002122112220100011112220010 |
4 | 122023121123001213010032 |
5 | 110042312144121013030 |
6 | 1044511034230534050 |
7 | 33152020465033050 |
oct | 3213313301470416 |
9 | 502575810145803 |
10 | 115132420485390 |
11 | 33759426960330 |
12 | 10ab5526807326 |
13 | 4c31c2c849209 |
14 | 20606204258d0 |
15 | d49cd25186b0 |
hex | 68b65b06710e |
115132420485390 has 256 divisors, whose sum is σ = 368173869613056. Its totient is φ = 22305914112000.
The previous prime is 115132420485367. The next prime is 115132420485391. The reversal of 115132420485390 is 93584024231511.
115132420485390 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115132420485391) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 9498186 + ... + 17901965.
It is an arithmetic number, because the mean of its divisors is an integer number (1438179178176).
Almost surely, 2115132420485390 is an apocalyptic number.
115132420485390 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115132420485390 is an abundant number, since it is smaller than the sum of its proper divisors (253041449127666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115132420485390 is a wasteful number, since it uses less digits than its factorization.
115132420485390 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27400303.
The product of its (nonzero) digits is 1036800, while the sum is 48.
The spelling of 115132420485390 in words is "one hundred fifteen trillion, one hundred thirty-two billion, four hundred twenty million, four hundred eighty-five thousand, three hundred ninety".
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