Base | Representation |
---|---|
bin | 110101100111001101… |
… | …1011100101001101001 |
3 | 102000011210000112010220 |
4 | 1223032123130221221 |
5 | 3341242401421213 |
6 | 124520252000253 |
7 | 11214042455466 |
oct | 1531633345151 |
9 | 360153015126 |
10 | 115132451433 |
11 | 449112a390a |
12 | 1a391760089 |
13 | ab1a92200c |
14 | 5802ac266d |
15 | 2edc9b3e23 |
hex | 1ace6dca69 |
115132451433 has 64 divisors (see below), whose sum is σ = 167162849280. Its totient is φ = 70263244800.
The previous prime is 115132451419. The next prime is 115132451443. The reversal of 115132451433 is 334154231511.
It is not a de Polignac number, because 115132451433 - 212 = 115132447337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115132451394 and 115132451403.
It is not an unprimeable number, because it can be changed into a prime (115132451443) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 42002443 + ... + 42005183.
It is an arithmetic number, because the mean of its divisors is an integer number (2611919520).
Almost surely, 2115132451433 is an apocalyptic number.
It is an amenable number.
115132451433 is a deficient number, since it is larger than the sum of its proper divisors (52030397847).
115132451433 is a wasteful number, since it uses less digits than its factorization.
115132451433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3038.
The product of its digits is 21600, while the sum is 33.
Adding to 115132451433 its reverse (334154231511), we get a palindrome (449286682944).
The spelling of 115132451433 in words is "one hundred fifteen billion, one hundred thirty-two million, four hundred fifty-one thousand, four hundred thirty-three".
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