Base | Representation |
---|---|
bin | 110101100111001101… |
… | …1011100101001110011 |
3 | 102000011210000112011021 |
4 | 1223032123130221303 |
5 | 3341242401421233 |
6 | 124520252000311 |
7 | 11214042455512 |
oct | 1531633345163 |
9 | 360153015137 |
10 | 115132451443 |
11 | 449112a3919 |
12 | 1a391760097 |
13 | ab1a922019 |
14 | 5802ac2679 |
15 | 2edc9b3e2d |
hex | 1ace6dca73 |
115132451443 has 2 divisors, whose sum is σ = 115132451444. Its totient is φ = 115132451442.
The previous prime is 115132451419. The next prime is 115132451477. The reversal of 115132451443 is 344154231511.
It is an a-pointer prime, because the next prime (115132451477) can be obtained adding 115132451443 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115132451443 - 221 = 115130354291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115132451399 and 115132451408.
It is not a weakly prime, because it can be changed into another prime (115132454443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566225721 + 57566225722.
It is an arithmetic number, because the mean of its divisors is an integer number (57566225722).
Almost surely, 2115132451443 is an apocalyptic number.
115132451443 is a deficient number, since it is larger than the sum of its proper divisors (1).
115132451443 is an equidigital number, since it uses as much as digits as its factorization.
115132451443 is an evil number, because the sum of its binary digits is even.
The product of its digits is 28800, while the sum is 34.
Adding to 115132451443 its reverse (344154231511), we get a palindrome (459286682954).
The spelling of 115132451443 in words is "one hundred fifteen billion, one hundred thirty-two million, four hundred fifty-one thousand, four hundred forty-three".
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