Base | Representation |
---|---|
bin | 1101101110011… |
… | …00100101111001 |
3 | 22000122100111112 |
4 | 12313030211321 |
5 | 213433222133 |
6 | 15231410105 |
7 | 2565420056 |
oct | 667144571 |
9 | 260570445 |
10 | 115132793 |
11 | 59a97a76 |
12 | 32683935 |
13 | 1ab11719 |
14 | 1141002d |
15 | a193648 |
hex | 6dcc979 |
115132793 has 2 divisors, whose sum is σ = 115132794. Its totient is φ = 115132792.
The previous prime is 115132769. The next prime is 115132847. The reversal of 115132793 is 397231511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90402064 + 24730729 = 9508^2 + 4973^2 .
It is an emirp because it is prime and its reverse (397231511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115132793 - 214 = 115116409 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (115132763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566396 + 57566397.
It is an arithmetic number, because the mean of its divisors is an integer number (57566397).
Almost surely, 2115132793 is an apocalyptic number.
It is an amenable number.
115132793 is a deficient number, since it is larger than the sum of its proper divisors (1).
115132793 is an equidigital number, since it uses as much as digits as its factorization.
115132793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5670, while the sum is 32.
The square root of 115132793 is about 10729.9950139783. The cubic root of 115132793 is about 486.4815193528.
The spelling of 115132793 in words is "one hundred fifteen million, one hundred thirty-two thousand, seven hundred ninety-three".
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