Base | Representation |
---|---|
bin | 100010010100000… |
… | …0001011000000011 |
3 | 2222020110020102101 |
4 | 1010220001120003 |
5 | 4324220421313 |
6 | 310125131231 |
7 | 40350150313 |
oct | 10450013003 |
9 | 2866406371 |
10 | 1151342083 |
11 | 5409a2391 |
12 | 2816b9b17 |
13 | 1546b8c08 |
14 | acca5443 |
15 | 6b1285dd |
hex | 44a01603 |
1151342083 has 2 divisors, whose sum is σ = 1151342084. Its totient is φ = 1151342082.
The previous prime is 1151342063. The next prime is 1151342099. The reversal of 1151342083 is 3802431511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1151342083 - 29 = 1151341571 is a prime.
It is not a weakly prime, because it can be changed into another prime (1151342063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575671041 + 575671042.
It is an arithmetic number, because the mean of its divisors is an integer number (575671042).
Almost surely, 21151342083 is an apocalyptic number.
1151342083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1151342083 is an equidigital number, since it uses as much as digits as its factorization.
1151342083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
The square root of 1151342083 is about 33931.4320800051. The cubic root of 1151342083 is about 1048.0969559867.
Adding to 1151342083 its reverse (3802431511), we get a palindrome (4953773594).
The spelling of 1151342083 in words is "one billion, one hundred fifty-one million, three hundred forty-two thousand, eighty-three".
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