115134373 has 2 divisors, whose sum is σ = 115134374. Its totient is φ = 115134372.

The previous prime is 115134337. The next prime is 115134407. The reversal of 115134373 is 373431511.

Together with previous prime (115134337) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101243844 + 13890529 = 10062^2 + 3727^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115134373 is a prime.

It is a super-2 number, since 2×115134373² = 26511847692206258, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115134473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57567186 + 57567187.

It is an arithmetic number, because the mean of its divisors is an integer number (57567187).

Almost surely, 2^115134373 is an apocalyptic number.

It is an amenable number.

115134373 is a deficient number, since it is larger than the sum of its proper divisors (1).

115134373 is an equidigital number, since it uses as much as digits as its factorization.

115134373 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3780, while the sum is 28.

The square root of 115134373 is about 10730.0686391094. The cubic root of 115134373 is about 486.4837447173.

Adding to 115134373 its reverse (373431511), we get a palindrome (488565884).

The spelling of 115134373 in words is "one hundred fifteen million, one hundred thirty-four thousand, three hundred seventy-three".