Base | Representation |
---|---|
bin | 11010001011011011111100… |
… | …000000110010110100011011 |
3 | 120002122210212120102101112201 |
4 | 122023123330000302310123 |
5 | 110042333212034400123 |
6 | 1044512202232551031 |
7 | 33152144432330641 |
oct | 3213337400626433 |
9 | 502583776371481 |
10 | 115135121403163 |
11 | 3375a592513884 |
12 | 10ab5b5b252477 |
13 | 4c32270294604 |
14 | 20607d9017191 |
15 | d49dde6d05ad |
hex | 68b6fc032d1b |
115135121403163 has 2 divisors, whose sum is σ = 115135121403164. Its totient is φ = 115135121403162.
The previous prime is 115135121402989. The next prime is 115135121403187. The reversal of 115135121403163 is 361304121531511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115135121403163 - 237 = 114997682449691 is a prime.
It is not a weakly prime, because it can be changed into another prime (115135121401163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57567560701581 + 57567560701582.
It is an arithmetic number, because the mean of its divisors is an integer number (57567560701582).
Almost surely, 2115135121403163 is an apocalyptic number.
115135121403163 is a deficient number, since it is larger than the sum of its proper divisors (1).
115135121403163 is an equidigital number, since it uses as much as digits as its factorization.
115135121403163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 37.
Adding to 115135121403163 its reverse (361304121531511), we get a palindrome (476439242934674).
The spelling of 115135121403163 in words is "one hundred fifteen trillion, one hundred thirty-five billion, one hundred twenty-one million, four hundred three thousand, one hundred sixty-three".
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