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11513536424354 = 25756768212177
BaseRepresentation
bin1010011110001011010000…
…1111111010100110100010
31111202200110011000222220002
42213202310033322212202
53002114210311034404
640253125015220002
72265553110601016
oct247426417724642
944680404028802
1011513536424354
113739955177378
12135b498077602
1365694cb0ca83
142bb38847c546
1514e76089ec1e
hexa78b43fa9a2

11513536424354 has 4 divisors (see below), whose sum is σ = 17270304636534. Its totient is φ = 5756768212176.

The previous prime is 11513536424323. The next prime is 11513536424387. The reversal of 11513536424354 is 45342463531511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10962237599329 + 551298825025 = 3310927^2 + 742495^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11513536424299 and 11513536424308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2878384106087 + ... + 2878384106090.

Almost surely, 211513536424354 is an apocalyptic number.

11513536424354 is a deficient number, since it is larger than the sum of its proper divisors (5756768212180).

11513536424354 is an equidigital number, since it uses as much as digits as its factorization.

11513536424354 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5756768212179.

The product of its digits is 2592000, while the sum is 47.

Adding to 11513536424354 its reverse (45342463531511), we get a palindrome (56855999955865).

The spelling of 11513536424354 in words is "eleven trillion, five hundred thirteen billion, five hundred thirty-six million, four hundred twenty-four thousand, three hundred fifty-four".

Divisors: 1 2 5756768212177 11513536424354