115140305548800 has 1440 divisors, whose sum is σ = 488816311087104. Its totient is φ = 25327116288000.

The previous prime is 115140305548787. The next prime is 115140305548889. The reversal of 115140305548800 is 8845503041511.

115140305548800 is a `hidden beast` number, since 1 + 1 + 5 + 14 + 0 + 3 + 0 + 554 + 8 + 80 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1440).

It is a super-3 number, since 3×115140305548800³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 4524697677 + ... + 4524723123.

Almost surely, 2^{115140305548800} is an apocalyptic number.

115140305548800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115140305548800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (244408155543552).

115140305548800 is an abundant number, since it is smaller than the sum of its proper divisors (373676005538304).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115140305548800 is a wasteful number, since it uses less digits than its factorization.

115140305548800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25700 (or 25676 counting only the distinct ones).

The product of its (nonzero) digits is 384000, while the sum is 45.

The spelling of 115140305548800 in words is "one hundred fifteen trillion, one hundred forty billion, three hundred five million, five hundred forty-eight thousand, eight hundred".