Base | Representation |
---|---|
bin | 110101100111011100… |
… | …1011111000000010101 |
3 | 102000012022211120012012 |
4 | 1223032321133000111 |
5 | 3341301410403042 |
6 | 124521132434005 |
7 | 11214166421606 |
oct | 1531671370025 |
9 | 360168746165 |
10 | 115140325397 |
11 | 44915791719 |
12 | 1a394318905 |
13 | ab1c44ac76 |
14 | 5803b71dad |
15 | 2edd51be82 |
hex | 1acee5f015 |
115140325397 has 2 divisors, whose sum is σ = 115140325398. Its totient is φ = 115140325396.
The previous prime is 115140325309. The next prime is 115140325403. The reversal of 115140325397 is 793523041511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110312993956 + 4827331441 = 332134^2 + 69479^2 .
It is a cyclic number.
It is not a de Polignac number, because 115140325397 - 210 = 115140324373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115140375397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57570162698 + 57570162699.
It is an arithmetic number, because the mean of its divisors is an integer number (57570162699).
Almost surely, 2115140325397 is an apocalyptic number.
It is an amenable number.
115140325397 is a deficient number, since it is larger than the sum of its proper divisors (1).
115140325397 is an equidigital number, since it uses as much as digits as its factorization.
115140325397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 41.
The spelling of 115140325397 in words is "one hundred fifteen billion, one hundred forty million, three hundred twenty-five thousand, three hundred ninety-seven".
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