Base | Representation |
---|---|
bin | 110101100111011110… |
… | …1010010010100101111 |
3 | 102000012101201012022120 |
4 | 1223032331102110233 |
5 | 3341302134301111 |
6 | 124521210044023 |
7 | 11214211042341 |
oct | 1531675222457 |
9 | 360171635276 |
10 | 115141322031 |
11 | 4491630248a |
12 | 1a394719613 |
13 | ab1c7097a8 |
14 | 5803d51291 |
15 | 2edd667406 |
hex | 1acef5252f |
115141322031 has 48 divisors (see below), whose sum is σ = 167481123840. Its totient is φ = 70323402240.
The previous prime is 115141321957. The next prime is 115141322053. The reversal of 115141322031 is 130223141511.
It is not a de Polignac number, because 115141322031 - 210 = 115141321007 is a prime.
It is a super-2 number, since 2×1151413220312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115141321992 and 115141322010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115141322831) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4851165 + ... + 4874841.
It is an arithmetic number, because the mean of its divisors is an integer number (3489190080).
Almost surely, 2115141322031 is an apocalyptic number.
115141322031 is a deficient number, since it is larger than the sum of its proper divisors (52339801809).
115141322031 is a wasteful number, since it uses less digits than its factorization.
115141322031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23864 (or 23847 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 115141322031 its reverse (130223141511), we get a palindrome (245364463542).
The spelling of 115141322031 in words is "one hundred fifteen billion, one hundred forty-one million, three hundred twenty-two thousand, thirty-one".
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