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11514252245117 is a prime number
BaseRepresentation
bin1010011110001101111011…
…1010100011100001111101
31111202202022000222110101012
42213203132322203201331
53002122142033320432
640253324025525005
72265606622144016
oct247433672434175
944682260873335
1011514252245117
11373a192242086
12135b657943765
13656a351cb25b
142bb41557400d
1514e7a3649cb2
hexa78deea387d

11514252245117 has 2 divisors, whose sum is σ = 11514252245118. Its totient is φ = 11514252245116.

The previous prime is 11514252245077. The next prime is 11514252245189. The reversal of 11514252245117 is 71154225241511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6049602644836 + 5464649600281 = 2459594^2 + 2337659^2 .

It is a cyclic number.

It is not a de Polignac number, because 11514252245117 - 210 = 11514252244093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11514252245017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757126122558 + 5757126122559.

It is an arithmetic number, because the mean of its divisors is an integer number (5757126122559).

Almost surely, 211514252245117 is an apocalyptic number.

It is an amenable number.

11514252245117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11514252245117 is an equidigital number, since it uses as much as digits as its factorization.

11514252245117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 112000, while the sum is 41.

Adding to 11514252245117 its reverse (71154225241511), we get a palindrome (82668477486628).

The spelling of 11514252245117 in words is "eleven trillion, five hundred fourteen billion, two hundred fifty-two million, two hundred forty-five thousand, one hundred seventeen".