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1151430125281 is a prime number
BaseRepresentation
bin10000110000010110100…
…101010110011011100001
311002002001010220211102121
4100300112211112123201
5122331112103002111
62240543143344241
7146121340402522
oct20602645263341
94062033824377
101151430125281
11404356319367
121671a3752081
138476bc13777
143da2db0c849
151ee40b8b871
hex10c169566e1

1151430125281 has 2 divisors, whose sum is σ = 1151430125282. Its totient is φ = 1151430125280.

The previous prime is 1151430125269. The next prime is 1151430125347. The reversal of 1151430125281 is 1825210341511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1076157264400 + 75272860881 = 1037380^2 + 274359^2 .

It is a cyclic number.

It is not a de Polignac number, because 1151430125281 - 239 = 601674311393 is a prime.

It is a super-2 number, since 2×11514301252812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1151430125201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575715062640 + 575715062641.

It is an arithmetic number, because the mean of its divisors is an integer number (575715062641).

Almost surely, 21151430125281 is an apocalyptic number.

It is an amenable number.

1151430125281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151430125281 is an equidigital number, since it uses as much as digits as its factorization.

1151430125281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 34.

Adding to 1151430125281 its reverse (1825210341511), we get a palindrome (2976640466792).

The spelling of 1151430125281 in words is "one trillion, one hundred fifty-one billion, four hundred thirty million, one hundred twenty-five thousand, two hundred eighty-one".