Base | Representation |
---|---|
bin | 110101100111101111… |
… | …0110001101000011011 |
3 | 102000020000020012211021 |
4 | 1223033132301220123 |
5 | 3341311411213034 |
6 | 124522122143311 |
7 | 11214345465142 |
oct | 1531736615033 |
9 | 360200205737 |
10 | 115150101019 |
11 | 44920259248 |
12 | 1a397651b37 |
13 | ab21491665 |
14 | 5805198759 |
15 | 2ede2ed6b4 |
hex | 1acf7b1a1b |
115150101019 has 2 divisors, whose sum is σ = 115150101020. Its totient is φ = 115150101018.
The previous prime is 115150100987. The next prime is 115150101023. The reversal of 115150101019 is 910101051511.
It is a strong prime.
It is an emirp because it is prime and its reverse (910101051511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115150101019 - 25 = 115150100987 is a prime.
It is a super-2 number, since 2×1151501010192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115150100984 and 115150101002.
It is not a weakly prime, because it can be changed into another prime (115150101049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57575050509 + 57575050510.
It is an arithmetic number, because the mean of its divisors is an integer number (57575050510).
Almost surely, 2115150101019 is an apocalyptic number.
115150101019 is a deficient number, since it is larger than the sum of its proper divisors (1).
115150101019 is an equidigital number, since it uses as much as digits as its factorization.
115150101019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225, while the sum is 25.
The spelling of 115150101019 in words is "one hundred fifteen billion, one hundred fifty million, one hundred one thousand, nineteen".
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