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115150112213151 = 338383370737717
BaseRepresentation
bin11010001011101001111001…
…100010001100100010011111
3120002201020120022021102220110
4122023221321202030202133
5110043104412211310101
61044523121542021103
733153215061163221
oct3213517142144237
9502636508242813
10115150112213151
1133765985429244
1210ab8a43717793
134c337bbc43692
14206141bd28411
15d4a4ba7cbcd6
hex68ba7988c89f

115150112213151 has 4 divisors (see below), whose sum is σ = 153533482950872. Its totient is φ = 76766741475432.

The previous prime is 115150112213119. The next prime is 115150112213159. The reversal of 115150112213151 is 151312211051511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 115150112213151 - 25 = 115150112213119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115150112213159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19191685368856 + ... + 19191685368861.

It is an arithmetic number, because the mean of its divisors is an integer number (38383370737718).

Almost surely, 2115150112213151 is an apocalyptic number.

115150112213151 is a deficient number, since it is larger than the sum of its proper divisors (38383370737721).

115150112213151 is an equidigital number, since it uses as much as digits as its factorization.

115150112213151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38383370737720.

The product of its (nonzero) digits is 1500, while the sum is 30.

Adding to 115150112213151 its reverse (151312211051511), we get a palindrome (266462323264662).

The spelling of 115150112213151 in words is "one hundred fifteen trillion, one hundred fifty billion, one hundred twelve million, two hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 3 38383370737717 115150112213151