115153330245013 has 2 divisors, whose sum is σ = 115153330245014. Its totient is φ = 115153330245012.

The previous prime is 115153330245007. The next prime is 115153330245059. The reversal of 115153330245013 is 310542033351511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69283282500964 + 45870047744049 = 8323658^2 + 6772743^2 .

It is a cyclic number.

It is not a de Polignac number, because 115153330245013 - 2⁹ = 115153330244501 is a prime.

It is a super-3 number, since 3×115153330245013³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115153330245313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576665122506 + 57576665122507.

It is an arithmetic number, because the mean of its divisors is an integer number (57576665122507).

Almost surely, 2^{115153330245013} is an apocalyptic number.

It is an amenable number.

115153330245013 is a deficient number, since it is larger than the sum of its proper divisors (1).

115153330245013 is an equidigital number, since it uses as much as digits as its factorization.

115153330245013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 115153330245013 its reverse (310542033351511), we get a palindrome (425695363596524).

The spelling of 115153330245013 in words is "one hundred fifteen trillion, one hundred fifty-three billion, three hundred thirty million, two hundred forty-five thousand, thirteen".