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115153412120353 is a prime number
BaseRepresentation
bin11010001011101100111110…
…001110010101111100100001
3120002201120002021122002120201
4122023230332032111330201
5110043133142000322403
61044524425222305201
733153362621011015
oct3213547616257441
9502646067562521
10115153412120353
113376731910a382
1210ab9604888201
134c33bc67c26a9
1420616522bc545
15d4a61036221d
hex68bb3e395f21

115153412120353 has 2 divisors, whose sum is σ = 115153412120354. Its totient is φ = 115153412120352.

The previous prime is 115153412120287. The next prime is 115153412120437. The reversal of 115153412120353 is 353021214351511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106875546591969 + 8277865528384 = 10338063^2 + 2877128^2 .

It is a cyclic number.

It is not a de Polignac number, because 115153412120353 - 213 = 115153412112161 is a prime.

It is a super-2 number, since 2×1151534121203532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115153412123353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576706060176 + 57576706060177.

It is an arithmetic number, because the mean of its divisors is an integer number (57576706060177).

Almost surely, 2115153412120353 is an apocalyptic number.

It is an amenable number.

115153412120353 is a deficient number, since it is larger than the sum of its proper divisors (1).

115153412120353 is an equidigital number, since it uses as much as digits as its factorization.

115153412120353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 37.

Adding to 115153412120353 its reverse (353021214351511), we get a palindrome (468174626471864).

The spelling of 115153412120353 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred twelve million, one hundred twenty thousand, three hundred fifty-three".