Base | Representation |
---|---|
bin | 11010001011101100111110… |
… | …001110010101111011011111 |
3 | 120002201120002021122002111021 |
4 | 122023230332032111323133 |
5 | 110043133142000322122 |
6 | 1044524425222305011 |
7 | 33153362621010562 |
oct | 3213547616257337 |
9 | 502646067562437 |
10 | 115153412120287 |
11 | 3376731910a322 |
12 | 10ab9604888167 |
13 | 4c33bc67c2658 |
14 | 20616522bc4d9 |
15 | d4a6103621c7 |
hex | 68bb3e395edf |
115153412120287 has 2 divisors, whose sum is σ = 115153412120288. Its totient is φ = 115153412120286.
The previous prime is 115153412120281. The next prime is 115153412120353. The reversal of 115153412120287 is 782021214351511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115153412120287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115153412120281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576706060143 + 57576706060144.
It is an arithmetic number, because the mean of its divisors is an integer number (57576706060144).
Almost surely, 2115153412120287 is an apocalyptic number.
115153412120287 is a deficient number, since it is larger than the sum of its proper divisors (1).
115153412120287 is an equidigital number, since it uses as much as digits as its factorization.
115153412120287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 43.
Adding to 115153412120287 its reverse (782021214351511), we get a palindrome (897174626471798).
The spelling of 115153412120287 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred twelve million, one hundred twenty thousand, two hundred eighty-seven".
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