115153414057301 has 2 divisors, whose sum is σ = 115153414057302. Its totient is φ = 115153414057300.

The previous prime is 115153414057291. The next prime is 115153414057307. The reversal of 115153414057301 is 103750414351511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97468033308100 + 17685380749201 = 9872590^2 + 4205399^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115153414057301 is a prime.

It is a super-2 number, since 2×115153414057301² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115153414057307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576707028650 + 57576707028651.

It is an arithmetic number, because the mean of its divisors is an integer number (57576707028651).

Almost surely, 2^{115153414057301} is an apocalyptic number.

It is an amenable number.

115153414057301 is a deficient number, since it is larger than the sum of its proper divisors (1).

115153414057301 is an equidigital number, since it uses as much as digits as its factorization.

115153414057301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126000, while the sum is 41.

The spelling of 115153414057301 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, fifty-seven thousand, three hundred one".