Search a number
-
+
115154435013049 is a prime number
BaseRepresentation
bin11010001011101101111011…
…001100010111100110111001
3120002201122201120101102120101
4122023231323030113212321
5110043142240330404144
61044525114522355401
733153430151316325
oct3213557314274671
9502648646342511
10115154435013049
11337677a3549843
1210ab984b35bb61
134c3402a6b6843
14206170c0a8985
15d4a6700666d4
hex68bb7b3179b9

115154435013049 has 2 divisors, whose sum is σ = 115154435013050. Its totient is φ = 115154435013048.

The previous prime is 115154435013029. The next prime is 115154435013061. The reversal of 115154435013049 is 940310534451511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84950969103225 + 30203465909824 = 9216885^2 + 5495768^2 .

It is a cyclic number.

It is not a de Polignac number, because 115154435013049 - 25 = 115154435013017 is a prime.

It is not a weakly prime, because it can be changed into another prime (115154435013029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57577217506524 + 57577217506525.

It is an arithmetic number, because the mean of its divisors is an integer number (57577217506525).

Almost surely, 2115154435013049 is an apocalyptic number.

It is an amenable number.

115154435013049 is a deficient number, since it is larger than the sum of its proper divisors (1).

115154435013049 is an equidigital number, since it uses as much as digits as its factorization.

115154435013049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648000, while the sum is 46.

The spelling of 115154435013049 in words is "one hundred fifteen trillion, one hundred fifty-four billion, four hundred thirty-five million, thirteen thousand, forty-nine".