Base | Representation |
---|---|
bin | 10101011100110101… |
… | …10111111101111011 |
3 | 1002201120210100022112 |
4 | 22232122313331323 |
5 | 142041122341123 |
6 | 5142424242535 |
7 | 555245133215 |
oct | 125632677573 |
9 | 32646710275 |
10 | 11516215163 |
11 | 497a66a9a2 |
12 | 229491044b |
13 | 1116b691cb |
14 | 7b36875b5 |
15 | 47605bd78 |
hex | 2ae6b7f7b |
11516215163 has 2 divisors, whose sum is σ = 11516215164. Its totient is φ = 11516215162.
The previous prime is 11516215159. The next prime is 11516215169. The reversal of 11516215163 is 36151261511.
It is a weak prime.
It is an emirp because it is prime and its reverse (36151261511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11516215163 - 22 = 11516215159 is a prime.
It is a super-2 number, since 2×115162151632 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11516215169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5758107581 + 5758107582.
It is an arithmetic number, because the mean of its divisors is an integer number (5758107582).
Almost surely, 211516215163 is an apocalyptic number.
11516215163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11516215163 is an equidigital number, since it uses as much as digits as its factorization.
11516215163 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 32.
Adding to 11516215163 its reverse (36151261511), we get a palindrome (47667476674).
The spelling of 11516215163 in words is "eleven billion, five hundred sixteen million, two hundred fifteen thousand, one hundred sixty-three".
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