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11519733284009 is a prime number
BaseRepresentation
bin1010011110100010010110…
…0111000011110010101001
31111210021110000112002020122
42213220211213003302221
53002214403210042014
640300031543333025
72266162505204156
oct247504547036251
944707400462218
1011519733284009
113741545135795
121360727451175
136573c9903632
142bb7b549322d
1514e9c492158e
hexa7a259c3ca9

11519733284009 has 2 divisors, whose sum is σ = 11519733284010. Its totient is φ = 11519733284008.

The previous prime is 11519733283963. The next prime is 11519733284023. The reversal of 11519733284009 is 90048233791511.

11519733284009 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6168283861609 + 5351449422400 = 2483603^2 + 2313320^2 .

It is a cyclic number.

It is not a de Polignac number, because 11519733284009 - 212 = 11519733279913 is a prime.

It is a super-2 number, since 2×115197332840092 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11519733284069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5759866642004 + 5759866642005.

It is an arithmetic number, because the mean of its divisors is an integer number (5759866642005).

Almost surely, 211519733284009 is an apocalyptic number.

It is an amenable number.

11519733284009 is a deficient number, since it is larger than the sum of its proper divisors (1).

11519733284009 is an equidigital number, since it uses as much as digits as its factorization.

11519733284009 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 53.

The spelling of 11519733284009 in words is "eleven trillion, five hundred nineteen billion, seven hundred thirty-three million, two hundred eighty-four thousand, nine".