Base | Representation |
---|---|
bin | 10000110000111001010… |
… | …011001000111011110101 |
3 | 11002010112201212021101122 |
4 | 100300321103020323311 |
5 | 122333310203211343 |
6 | 2241121031033325 |
7 | 146141642066411 |
oct | 20607123107365 |
9 | 4063481767348 |
10 | 1152012553973 |
11 | 404625065696 |
12 | 16732680b845 |
13 | 84832799528 |
14 | 3da871ddd41 |
15 | 1ee76d88068 |
hex | 10c394c8ef5 |
1152012553973 has 2 divisors, whose sum is σ = 1152012553974. Its totient is φ = 1152012553972.
The previous prime is 1152012553963. The next prime is 1152012554113. The reversal of 1152012553973 is 3793552102511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 868965145489 + 283047408484 = 932183^2 + 532022^2 .
It is a cyclic number.
It is not a de Polignac number, because 1152012553973 - 214 = 1152012537589 is a prime.
It is a super-2 number, since 2×11520125539732 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1152012553963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576006276986 + 576006276987.
It is an arithmetic number, because the mean of its divisors is an integer number (576006276987).
Almost surely, 21152012553973 is an apocalyptic number.
It is an amenable number.
1152012553973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152012553973 is an equidigital number, since it uses as much as digits as its factorization.
1152012553973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 283500, while the sum is 44.
The spelling of 1152012553973 in words is "one trillion, one hundred fifty-two billion, twelve million, five hundred fifty-three thousand, nine hundred seventy-three".
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