Base | Representation |
---|---|
bin | 100010010101010… |
… | …0101110000110101 |
3 | 2222021201110001112 |
4 | 1010222211300311 |
5 | 4324403443123 |
6 | 310151404405 |
7 | 40355653343 |
oct | 10452456065 |
9 | 2867643045 |
10 | 1152015413 |
11 | 54131225a |
12 | 281983705 |
13 | 154893533 |
14 | acddc993 |
15 | 6b20cd78 |
hex | 44aa5c35 |
1152015413 has 2 divisors, whose sum is σ = 1152015414. Its totient is φ = 1152015412.
The previous prime is 1152015383. The next prime is 1152015433. The reversal of 1152015413 is 3145102511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 756085009 + 395930404 = 27497^2 + 19898^2 .
It is an emirp because it is prime and its reverse (3145102511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1152015413 - 28 = 1152015157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1152015433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576007706 + 576007707.
It is an arithmetic number, because the mean of its divisors is an integer number (576007707).
Almost surely, 21152015413 is an apocalyptic number.
It is an amenable number.
1152015413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152015413 is an equidigital number, since it uses as much as digits as its factorization.
1152015413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 23.
The square root of 1152015413 is about 33941.3525511285. The cubic root of 1152015413 is about 1048.3012328348.
Adding to 1152015413 its reverse (3145102511), we get a palindrome (4297117924).
The spelling of 1152015413 in words is "one billion, one hundred fifty-two million, fifteen thousand, four hundred thirteen".
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