Base | Representation |
---|---|
bin | 10000110000111010011… |
… | …110100011101110010001 |
3 | 11002010121010001201110021 |
4 | 100300322132203232101 |
5 | 122333330233340442 |
6 | 2241123014503441 |
7 | 146142302121415 |
oct | 20607236435621 |
9 | 4063533051407 |
10 | 1152032324497 |
11 | 40463523956a |
12 | 167331364b81 |
13 | 848368cc372 |
14 | 3da89aa8d45 |
15 | 1ee78990e67 |
hex | 10c3a7a3b91 |
1152032324497 has 2 divisors, whose sum is σ = 1152032324498. Its totient is φ = 1152032324496.
The previous prime is 1152032324479. The next prime is 1152032324533. The reversal of 1152032324497 is 7944232302511.
It is a happy number.
Together with previous prime (1152032324479) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1145935994256 + 6096330241 = 1070484^2 + 78079^2 .
It is a cyclic number.
It is not a de Polignac number, because 1152032324497 - 27 = 1152032324369 is a prime.
It is a super-2 number, since 2×11520323244972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1152032324407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576016162248 + 576016162249.
It is an arithmetic number, because the mean of its divisors is an integer number (576016162249).
Almost surely, 21152032324497 is an apocalyptic number.
It is an amenable number.
1152032324497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152032324497 is an equidigital number, since it uses as much as digits as its factorization.
1152032324497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 1152032324497 in words is "one trillion, one hundred fifty-two billion, thirty-two million, three hundred twenty-four thousand, four hundred ninety-seven".
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