Base | Representation |
---|---|
bin | 1010011110100101101010… |
… | …0110000000010100010011 |
3 | 1111210100201222011200212012 |
4 | 2213221122212000110103 |
5 | 3002223213240400313 |
6 | 40300300100053135 |
7 | 2266223520650213 |
oct | 247513246002423 |
9 | 44710658150765 |
10 | 11520622200083 |
11 | 3741960987577 |
12 | 13609350941ab |
13 | 65750bb18c89 |
14 | 2bb85b566243 |
15 | 14ea279adda8 |
hex | a7a5a980513 |
11520622200083 has 2 divisors, whose sum is σ = 11520622200084. Its totient is φ = 11520622200082.
The previous prime is 11520622199987. The next prime is 11520622200121. The reversal of 11520622200083 is 38000222602511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11520622200083 - 222 = 11520618005779 is a prime.
It is not a weakly prime, because it can be changed into another prime (11520622220083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760311100041 + 5760311100042.
It is an arithmetic number, because the mean of its divisors is an integer number (5760311100042).
Almost surely, 211520622200083 is an apocalyptic number.
11520622200083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520622200083 is an equidigital number, since it uses as much as digits as its factorization.
11520622200083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 11520622200083 its reverse (38000222602511), we get a palindrome (49520844802594).
The spelling of 11520622200083 in words is "eleven trillion, five hundred twenty billion, six hundred twenty-two million, two hundred thousand, eighty-three".
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