Base | Representation |
---|---|
bin | 1010011110100101101111… |
… | …0111000111111100110101 |
3 | 1111210100210110012001212012 |
4 | 2213221123313013330311 |
5 | 3002223234211340023 |
6 | 40300302135534005 |
7 | 2266224166465124 |
oct | 247513367077465 |
9 | 44710713161765 |
10 | 11520643465013 |
11 | 37419719911a1 |
12 | 136094022a305 |
13 | 657513353087 |
14 | 2bb8602ddabb |
15 | 14ea297ae978 |
hex | a7a5bdc7f35 |
11520643465013 has 2 divisors, whose sum is σ = 11520643465014. Its totient is φ = 11520643465012.
The previous prime is 11520643464961. The next prime is 11520643465027. The reversal of 11520643465013 is 31056434602511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10444938450769 + 1075705014244 = 3231863^2 + 1037162^2 .
It is a cyclic number.
It is not a de Polignac number, because 11520643465013 - 26 = 11520643464949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11520643465213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760321732506 + 5760321732507.
It is an arithmetic number, because the mean of its divisors is an integer number (5760321732507).
Almost surely, 211520643465013 is an apocalyptic number.
It is an amenable number.
11520643465013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520643465013 is an equidigital number, since it uses as much as digits as its factorization.
11520643465013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 11520643465013 in words is "eleven trillion, five hundred twenty billion, six hundred forty-three million, four hundred sixty-five thousand, thirteen".
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