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1152233968981 is a prime number
BaseRepresentation
bin10000110001000110011…
…111110001010101010101
311002011010011111022200111
4100301012133301111111
5122334233344001411
62241155020443021
7146150301065254
oct20610637612525
94064104438614
101152233968981
11404729044aa7
121673889a9471
1384869611024
143daa879879b
151ee8b522721
hex10c467f1555

1152233968981 has 2 divisors, whose sum is σ = 1152233968982. Its totient is φ = 1152233968980.

The previous prime is 1152233968939. The next prime is 1152233968993. The reversal of 1152233968981 is 1898693322511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 787851512100 + 364382456881 = 887610^2 + 603641^2 .

It is an emirp because it is prime and its reverse (1898693322511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1152233968981 - 225 = 1152200414549 is a prime.

It is a super-2 number, since 2×11522339689812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1152233962981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576116984490 + 576116984491.

It is an arithmetic number, because the mean of its divisors is an integer number (576116984491).

Almost surely, 21152233968981 is an apocalyptic number.

It is an amenable number.

1152233968981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152233968981 is an equidigital number, since it uses as much as digits as its factorization.

1152233968981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5598720, while the sum is 58.

The spelling of 1152233968981 in words is "one trillion, one hundred fifty-two billion, two hundred thirty-three million, nine hundred sixty-eight thousand, nine hundred eighty-one".