Base | Representation |
---|---|
bin | 11010001100101111101111… |
… | …110101111001001110001111 |
3 | 120002222102011010201121120101 |
4 | 122030233233311321032033 |
5 | 110100322012023014211 |
6 | 1045021404021431531 |
7 | 33161511451653565 |
oct | 3214575765711617 |
9 | 502872133647511 |
10 | 115225111532431 |
11 | 3379477160293a |
12 | 10b0b49486b5a7 |
13 | 4c3a8b203bb04 |
14 | 2064cd48a5a35 |
15 | d4c409c5c5c1 |
hex | 68cbefd7938f |
115225111532431 has 2 divisors, whose sum is σ = 115225111532432. Its totient is φ = 115225111532430.
The previous prime is 115225111532351. The next prime is 115225111532471. The reversal of 115225111532431 is 134235111522511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115225111532431 - 29 = 115225111531919 is a prime.
It is a super-2 number, since 2×1152251115324312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115225111532471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612555766215 + 57612555766216.
It is an arithmetic number, because the mean of its divisors is an integer number (57612555766216).
Almost surely, 2115225111532431 is an apocalyptic number.
115225111532431 is a deficient number, since it is larger than the sum of its proper divisors (1).
115225111532431 is an equidigital number, since it uses as much as digits as its factorization.
115225111532431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36000, while the sum is 37.
The spelling of 115225111532431 in words is "one hundred fifteen trillion, two hundred twenty-five billion, one hundred eleven million, five hundred thirty-two thousand, four hundred thirty-one".
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