Base | Representation |
---|---|
bin | 11010001100101111111110… |
… | …010000101111011011011111 |
3 | 120002222102202222221100202221 |
4 | 122030233332100233123133 |
5 | 110100323010440414411 |
6 | 1045021444022530211 |
7 | 33161520450150322 |
oct | 3214577620573337 |
9 | 502872688840687 |
10 | 115225353451231 |
11 | 33794886117031 |
12 | 10b0b541896967 |
13 | 4c3a9201b212a |
14 | 2064d18a7a7b9 |
15 | d4c4210e7071 |
hex | 68cbfe42f6df |
115225353451231 has 2 divisors, whose sum is σ = 115225353451232. Its totient is φ = 115225353451230.
The previous prime is 115225353451147. The next prime is 115225353451259. The reversal of 115225353451231 is 132154353522511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115225353451231 - 29 = 115225353450719 is a prime.
It is a super-2 number, since 2×1152253534512312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115225353454231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57612676725615 + 57612676725616.
It is an arithmetic number, because the mean of its divisors is an integer number (57612676725616).
Almost surely, 2115225353451231 is an apocalyptic number.
115225353451231 is a deficient number, since it is larger than the sum of its proper divisors (1).
115225353451231 is an equidigital number, since it uses as much as digits as its factorization.
115225353451231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 540000, while the sum is 43.
The spelling of 115225353451231 in words is "one hundred fifteen trillion, two hundred twenty-five billion, three hundred fifty-three million, four hundred fifty-one thousand, two hundred thirty-one".
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