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115230344040697 is a prime number
BaseRepresentation
bin11010001100110100100111…
…101110010101000011111001
3120002222220122210121120111211
4122030310213232111003321
5110100413221033300242
61045024031140323121
733162055226361664
oct3214644756250371
9502886583546454
10115230344040697
1133796a07186836
1210b104b50a34a1
134c3b2370c7552
14206526d7ac6db
15d4c6142e0317
hex68cd27b950f9

115230344040697 has 2 divisors, whose sum is σ = 115230344040698. Its totient is φ = 115230344040696.

The previous prime is 115230344040619. The next prime is 115230344040731. The reversal of 115230344040697 is 796040443032511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111928549777641 + 3301794263056 = 10579629^2 + 1817084^2 .

It is a cyclic number.

It is not a de Polignac number, because 115230344040697 - 231 = 115228196557049 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115230344040697.

It is not a weakly prime, because it can be changed into another prime (115230344040397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615172020348 + 57615172020349.

It is an arithmetic number, because the mean of its divisors is an integer number (57615172020349).

Almost surely, 2115230344040697 is an apocalyptic number.

It is an amenable number.

115230344040697 is a deficient number, since it is larger than the sum of its proper divisors (1).

115230344040697 is an equidigital number, since it uses as much as digits as its factorization.

115230344040697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2177280, while the sum is 49.

The spelling of 115230344040697 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred forty-four million, forty thousand, six hundred ninety-seven".