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115230350352157 is a prime number
BaseRepresentation
bin11010001100110100101000…
…000110011001111100011101
3120002222220200020111020012121
4122030310220012121330131
5110100413224142232112
61045024031523502541
733162055334126515
oct3214645006317435
9502886606436177
10115230350352157
1133796a0a7a7717
1210b104b7227a51
134c3b2384c7241
142065270572845
15d4c614b3a407
hex68cd28199f1d

115230350352157 has 2 divisors, whose sum is σ = 115230350352158. Its totient is φ = 115230350352156.

The previous prime is 115230350352151. The next prime is 115230350352199. The reversal of 115230350352157 is 751253053032511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90520115810436 + 24710234541721 = 9514206^2 + 4970939^2 .

It is a cyclic number.

It is not a de Polignac number, because 115230350352157 - 23 = 115230350352149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115230350352151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615175176078 + 57615175176079.

It is an arithmetic number, because the mean of its divisors is an integer number (57615175176079).

Almost surely, 2115230350352157 is an apocalyptic number.

It is an amenable number.

115230350352157 is a deficient number, since it is larger than the sum of its proper divisors (1).

115230350352157 is an equidigital number, since it uses as much as digits as its factorization.

115230350352157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 472500, while the sum is 43.

The spelling of 115230350352157 in words is "one hundred fifteen trillion, two hundred thirty billion, three hundred fifty million, three hundred fifty-two thousand, one hundred fifty-seven".