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115231242215113 is a prime number
BaseRepresentation
bin11010001100110101011101…
…010000100101111011001001
3120002222222222101200120011221
4122030311131100211323021
5110100422041001340423
61045024300223322041
733162116413625203
oct3214653520457311
9502888871616157
10115231242215113
1133797328181542
1210b10705a50321
134c3b34b201cbb
142065316bb1773
15d4c6680aae5d
hex68cd5d425ec9

115231242215113 has 2 divisors, whose sum is σ = 115231242215114. Its totient is φ = 115231242215112.

The previous prime is 115231242215041. The next prime is 115231242215129. The reversal of 115231242215113 is 311512242132511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102673879027344 + 12557363187769 = 10132812^2 + 3543637^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115231242215113 is a prime.

It is not a weakly prime, because it can be changed into another prime (115231242210113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615621107556 + 57615621107557.

It is an arithmetic number, because the mean of its divisors is an integer number (57615621107557).

Almost surely, 2115231242215113 is an apocalyptic number.

It is an amenable number.

115231242215113 is a deficient number, since it is larger than the sum of its proper divisors (1).

115231242215113 is an equidigital number, since it uses as much as digits as its factorization.

115231242215113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 34.

Adding to 115231242215113 its reverse (311512242132511), we get a palindrome (426743484347624).

The spelling of 115231242215113 in words is "one hundred fifteen trillion, two hundred thirty-one billion, two hundred forty-two million, two hundred fifteen thousand, one hundred thirteen".