Base | Representation |
---|---|
bin | 11010001100110101011101… |
… | …010000100101111100000011 |
3 | 120002222222222101200120021002 |
4 | 122030311131100211330003 |
5 | 110100422041001341141 |
6 | 1045024300223322215 |
7 | 33162116413625315 |
oct | 3214653520457403 |
9 | 502888871616232 |
10 | 115231242215171 |
11 | 33797328181595 |
12 | 10b10705a5036b |
13 | 4c3b34b202034 |
14 | 2065316bb17b5 |
15 | d4c6680aae9b |
hex | 68cd5d425f03 |
115231242215171 has 2 divisors, whose sum is σ = 115231242215172. Its totient is φ = 115231242215170.
The previous prime is 115231242215129. The next prime is 115231242215179. The reversal of 115231242215171 is 171512242132511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115231242215171 - 222 = 115231238020867 is a prime.
It is not a weakly prime, because it can be changed into another prime (115231242215179) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57615621107585 + 57615621107586.
It is an arithmetic number, because the mean of its divisors is an integer number (57615621107586).
Almost surely, 2115231242215171 is an apocalyptic number.
115231242215171 is a deficient number, since it is larger than the sum of its proper divisors (1).
115231242215171 is an equidigital number, since it uses as much as digits as its factorization.
115231242215171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 33600, while the sum is 38.
Adding to 115231242215171 its reverse (171512242132511), we get a palindrome (286743484347682).
The spelling of 115231242215171 in words is "one hundred fifteen trillion, two hundred thirty-one billion, two hundred forty-two million, two hundred fifteen thousand, one hundred seventy-one".
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