Base | Representation |
---|---|
bin | 10101011101101100… |
… | …11010011001100001 |
3 | 1002202002101002210212 |
4 | 22232312122121201 |
5 | 142044444342311 |
6 | 5143243103505 |
7 | 555363400505 |
oct | 125666323141 |
9 | 32662332725 |
10 | 11523434081 |
11 | 4983750645 |
12 | 2297211b95 |
13 | 11184c5c63 |
14 | 7b4606305 |
15 | 4769d5c8b |
hex | 2aed9a661 |
11523434081 has 2 divisors, whose sum is σ = 11523434082. Its totient is φ = 11523434080.
The previous prime is 11523434063. The next prime is 11523434141. The reversal of 11523434081 is 18043432511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8203830625 + 3319603456 = 90575^2 + 57616^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11523434081 is a prime.
It is a super-2 number, since 2×115234340812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11523434011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761717040 + 5761717041.
It is an arithmetic number, because the mean of its divisors is an integer number (5761717041).
Almost surely, 211523434081 is an apocalyptic number.
It is an amenable number.
11523434081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11523434081 is an equidigital number, since it uses as much as digits as its factorization.
11523434081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 11523434081 its reverse (18043432511), we get a palindrome (29566866592).
The spelling of 11523434081 in words is "eleven billion, five hundred twenty-three million, four hundred thirty-four thousand, eighty-one".
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