Base | Representation |
---|---|
bin | 1010011110110000011111… |
… | …1111111011001111110111 |
3 | 1111210122020201110002012012 |
4 | 2213230013333323033313 |
5 | 3002300143023002211 |
6 | 40301500503314435 |
7 | 2266355565130334 |
oct | 247540777731767 |
9 | 44718221402165 |
10 | 11523531453431 |
11 | 37431140a6688 |
12 | 136140744ba1b |
13 | 65788377976a |
14 | 2bba55aa998b |
15 | 14eb480c9d8b |
hex | a7b07ffb3f7 |
11523531453431 has 2 divisors, whose sum is σ = 11523531453432. Its totient is φ = 11523531453430.
The previous prime is 11523531453419. The next prime is 11523531453437. The reversal of 11523531453431 is 13435413532511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11523531453431 is a prime.
It is a super-2 number, since 2×115235314534312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11523531453437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761765726715 + 5761765726716.
It is an arithmetic number, because the mean of its divisors is an integer number (5761765726716).
Almost surely, 211523531453431 is an apocalyptic number.
11523531453431 is a deficient number, since it is larger than the sum of its proper divisors (1).
11523531453431 is an equidigital number, since it uses as much as digits as its factorization.
11523531453431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 324000, while the sum is 41.
Adding to 11523531453431 its reverse (13435413532511), we get a palindrome (24958944985942).
The spelling of 11523531453431 in words is "eleven trillion, five hundred twenty-three billion, five hundred thirty-one million, four hundred fifty-three thousand, four hundred thirty-one".
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