Base | Representation |
---|---|
bin | 110101101010011111… |
… | …1010001010000110111 |
3 | 102000110110002211121222 |
4 | 1223110333101100313 |
5 | 3342004040132041 |
6 | 124535222500555 |
7 | 11216550063245 |
oct | 1532477212067 |
9 | 360413084558 |
10 | 115242505271 |
11 | 449684319a3 |
12 | 1a40259475b |
13 | ab37675a2a |
14 | 581356d795 |
15 | 2ee74a274b |
hex | 1ad4fd1437 |
115242505271 has 2 divisors, whose sum is σ = 115242505272. Its totient is φ = 115242505270.
The previous prime is 115242505241. The next prime is 115242505387. The reversal of 115242505271 is 172505242511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115242505271 - 26 = 115242505207 is a prime.
It is a super-2 number, since 2×1152425052712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115242505241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57621252635 + 57621252636.
It is an arithmetic number, because the mean of its divisors is an integer number (57621252636).
Almost surely, 2115242505271 is an apocalyptic number.
115242505271 is a deficient number, since it is larger than the sum of its proper divisors (1).
115242505271 is an equidigital number, since it uses as much as digits as its factorization.
115242505271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28000, while the sum is 35.
Adding to 115242505271 its reverse (172505242511), we get a palindrome (287747747782).
The spelling of 115242505271 in words is "one hundred fifteen billion, two hundred forty-two million, five hundred five thousand, two hundred seventy-one".
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