Base | Representation |
---|---|
bin | 110101101010011111… |
… | …1010001010110101011 |
3 | 102000110110002212010202 |
4 | 1223110333101112223 |
5 | 3342004040140033 |
6 | 124535222502415 |
7 | 11216550064316 |
oct | 1532477212653 |
9 | 360413085122 |
10 | 115242505643 |
11 | 44968432201 |
12 | 1a402594a0b |
13 | ab37675c55 |
14 | 581356d97d |
15 | 2ee74a28e8 |
hex | 1ad4fd15ab |
115242505643 has 2 divisors, whose sum is σ = 115242505644. Its totient is φ = 115242505642.
The previous prime is 115242505633. The next prime is 115242505667. The reversal of 115242505643 is 346505242511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115242505643 - 28 = 115242505387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115242505597 and 115242505606.
It is not a weakly prime, because it can be changed into another prime (115242505603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57621252821 + 57621252822.
It is an arithmetic number, because the mean of its divisors is an integer number (57621252822).
Almost surely, 2115242505643 is an apocalyptic number.
115242505643 is a deficient number, since it is larger than the sum of its proper divisors (1).
115242505643 is an equidigital number, since it uses as much as digits as its factorization.
115242505643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 38.
The spelling of 115242505643 in words is "one hundred fifteen billion, two hundred forty-two million, five hundred five thousand, six hundred forty-three".
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