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1152432315214 = 2576216157607
BaseRepresentation
bin10000110001010010010…
…100011001101101001110
311002011121222201100120021
4100301102110121231032
5122340140133041324
62241230424012354
7146155230024205
oct20612224315516
94064558640507
101152432315214
1140481aaa8504
121674233010ba
138489b73966b
143dac6c6a23c
151ee9db51ae4
hex10c52519b4e

1152432315214 has 4 divisors (see below), whose sum is σ = 1728648472824. Its totient is φ = 576216157606.

The previous prime is 1152432315143. The next prime is 1152432315227. The reversal of 1152432315214 is 4125132342511.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11524323152142 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1152432315214.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 288108078802 + ... + 288108078805.

It is an arithmetic number, because the mean of its divisors is an integer number (432162118206).

Almost surely, 21152432315214 is an apocalyptic number.

1152432315214 is a deficient number, since it is larger than the sum of its proper divisors (576216157610).

1152432315214 is an equidigital number, since it uses as much as digits as its factorization.

1152432315214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 576216157609.

The product of its digits is 28800, while the sum is 34.

Adding to 1152432315214 its reverse (4125132342511), we get a palindrome (5277564657725).

The spelling of 1152432315214 in words is "one trillion, one hundred fifty-two billion, four hundred thirty-two million, three hundred fifteen thousand, two hundred fourteen".

Divisors: 1 2 576216157607 1152432315214