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115243361133541 is a prime number
BaseRepresentation
bin11010001101000000101111…
…100110100110001111100101
3120010001011020222120101221121
4122031000233212212033211
5110101121400422233131
61045034022542013541
733163025631006664
oct3215005746461745
9503034228511847
10115243361133541
11337a1486a76303
1210b12b285772b1
134c3c52cba2354
142065b46506ddb
15d4cb26ebb911
hex68d02f9a63e5

115243361133541 has 2 divisors, whose sum is σ = 115243361133542. Its totient is φ = 115243361133540.

The previous prime is 115243361133449. The next prime is 115243361133583. The reversal of 115243361133541 is 145331163342511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104690836277316 + 10552524856225 = 10231854^2 + 3248465^2 .

It is a cyclic number.

It is not a de Polignac number, because 115243361133541 - 215 = 115243361100773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115243361131541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57621680566770 + 57621680566771.

It is an arithmetic number, because the mean of its divisors is an integer number (57621680566771).

Almost surely, 2115243361133541 is an apocalyptic number.

It is an amenable number.

115243361133541 is a deficient number, since it is larger than the sum of its proper divisors (1).

115243361133541 is an equidigital number, since it uses as much as digits as its factorization.

115243361133541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 388800, while the sum is 43.

The spelling of 115243361133541 in words is "one hundred fifteen trillion, two hundred forty-three billion, three hundred sixty-one million, one hundred thirty-three thousand, five hundred forty-one".