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1152512351311 is a prime number
BaseRepresentation
bin10000110001010111000…
…101101101110001001111
311002011211120022121110011
4100301113011231301033
5122340321130220221
62241242403254051
7146160221230456
oct20612705556117
94064746277404
101152512351311
114048611a3842
1216744607a327
13848b21b02b9
143dad3741b9d
151eea5bb11e1
hex10c5716dc4f

1152512351311 has 2 divisors, whose sum is σ = 1152512351312. Its totient is φ = 1152512351310.

The previous prime is 1152512351297. The next prime is 1152512351411. The reversal of 1152512351311 is 1131532152511.

It is a weak prime.

It is an emirp because it is prime and its reverse (1131532152511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1152512351311 - 213 = 1152512343119 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1152512351411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576256175655 + 576256175656.

It is an arithmetic number, because the mean of its divisors is an integer number (576256175656).

Almost surely, 21152512351311 is an apocalyptic number.

1152512351311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152512351311 is an equidigital number, since it uses as much as digits as its factorization.

1152512351311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4500, while the sum is 31.

The spelling of 1152512351311 in words is "one trillion, one hundred fifty-two billion, five hundred twelve million, three hundred fifty-one thousand, three hundred eleven".