Base | Representation |
---|---|
bin | 10101011101111001… |
… | …11011111000011101 |
3 | 1002202012120222111122 |
4 | 22232330323320131 |
5 | 142100414102333 |
6 | 5143343500325 |
7 | 555414052121 |
oct | 125674737035 |
9 | 32665528448 |
10 | 11525144093 |
11 | 4984709381 |
12 | 22978b76a5 |
13 | 11189743b8 |
14 | 7b492d581 |
15 | 476c22798 |
hex | 2aef3be1d |
11525144093 has 2 divisors, whose sum is σ = 11525144094. Its totient is φ = 11525144092.
The previous prime is 11525144053. The next prime is 11525144107. The reversal of 11525144093 is 39044152511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11329899364 + 195244729 = 106442^2 + 13973^2 .
It is a cyclic number.
It is not a de Polignac number, because 11525144093 - 226 = 11458035229 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11525144003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762572046 + 5762572047.
It is an arithmetic number, because the mean of its divisors is an integer number (5762572047).
Almost surely, 211525144093 is an apocalyptic number.
It is an amenable number.
11525144093 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525144093 is an equidigital number, since it uses as much as digits as its factorization.
11525144093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 11525144093 in words is "eleven billion, five hundred twenty-five million, one hundred forty-four thousand, ninety-three".
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